2x^2+48x+64=-3x^2

Solution for 2x^2+48x+64=-3x^2 equation:

2x^2+48x+64=-3x^2

We move all terms to the left:

2x^2+48x+64-(-3x^2)=0

We get rid of parentheses

2x^2+3x^2+48x+64=0

We add all the numbers together, and all the variables

5x^2+48x+64=0

a = 5; b = 48; c = +64;
Δ = b2-4ac
Δ = 482-4·5·64
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-32}{2*5}=\frac{-80}{10}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+32}{2*5}=\frac{-16}{10}
=-1+3/5
$